diff options
author | Thomas Voss <thomasvoss@live.com> | 2021-12-08 07:02:51 +0100 |
---|---|---|
committer | Thomas Voss <thomasvoss@live.com> | 2021-12-08 07:02:51 +0100 |
commit | cc86bc72ff7c1625dd9e05027f6c7a740604237b (patch) | |
tree | ed9cf6db2dc4e14bab8d7aa6d03834c4909c9020 /2021/08/puzzle-2.py | |
parent | a761086de13f9ea01ad90dca12b235967804e526 (diff) |
Add day 8 solutions
Diffstat (limited to '2021/08/puzzle-2.py')
-rwxr-xr-x | 2021/08/puzzle-2.py | 55 |
1 files changed, 55 insertions, 0 deletions
diff --git a/2021/08/puzzle-2.py b/2021/08/puzzle-2.py new file mode 100755 index 0000000..010258f --- /dev/null +++ b/2021/08/puzzle-2.py @@ -0,0 +1,55 @@ +#!/usr/bin/env python3 + +import itertools + + +def solve(nums: list[str]) -> int: + nummap: dict[str, set[str]] = {} + + # First pass, find the easy patterns. From these 4 patterns you can determine all other ones + for n in nums: + nummap[[0, 0, 1, 7, 4, 0, 0, 8][len(n)]] = set(n) + + # Second pass, here we use the magic of sets to work out all the other numbers from the 4 + # that we found above + for n in nums: + match len((s := set(n))): + # 2, 3, or 5 + case 5: + # 1 is a subset of 3 and none of the others + if nummap[1].issubset(s): + nummap[3] = s + # 4 is a subset of 5 union with 1 but not 2 union with 1 + elif set(nummap[4]).issubset(set(s).union(set(nummap[1]))): + nummap[5] = s + else: + nummap[2] = s + # 0, 6, or 9 + case 6: + # 1 is a subset of 6 but not 0 or 9 + if not set(nummap[1]).issubset(set(s)): + nummap[6] = s + # 4 is a subset of 9 but not 0 + elif set(nummap[4]).issubset(set(s)): + nummap[9] = s + else: + nummap[0] = s + + nums = nums[nums.index("|") + 1 :] + + acc = 0 + for n, (k, v) in itertools.product(nums, nummap.items()): + if set(v) == set(n): + acc = acc * 10 + int(k) + return acc + + +def main() -> None: + with open("input", "r", encoding="utf-8") as f: + data = list(map(lambda l: l.strip().split(), f.readlines())) + + print(sum(solve(line) for line in data)) + + +if __name__ == "__main__": + main() |