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-rwxr-xr-x2020/13/puzzle-2.py40
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+#!/usr/bin/env python3
+
+from functools import reduce
+
+
+def chinese_remainder(n: tuple[int, ...], a: tuple[int, ...]) -> int:
+ sum = 0
+ prod = reduce(lambda a, b: a * b, n)
+ for n_i, a_i in zip(n, a):
+ p = prod // n_i
+ sum += a_i * mul_inv(p, n_i) * p
+ return sum % prod
+
+
+def mul_inv(a: int, b: int) -> int:
+ b0 = b
+ x0, x1 = 0, 1
+ if b == 1:
+ return 1
+ while a > 1:
+ q = a // b
+ a, b = b, a % b
+ x0, x1 = x1 - q * x0, x0
+ if x1 < 0:
+ x1 += b0
+ return x1
+
+
+def main() -> None:
+ with open("input", "r") as f:
+ ids = tuple(map(lambda x: int(x) if x.isdigit() else x, f.readlines()[1].split(",")))
+
+ buses = tuple(filter(lambda x: x != "x", ids))
+ modres = tuple(x if (x := bus - ids.index(bus)) != bus else 0 for bus in buses)
+
+ print(chinese_remainder(buses, modres))
+
+
+if __name__ == "__main__":
+ main()