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/* Simple formatter for mintage files. This is not perfect and doesn’t
check for syntactic correctness, it’s just to get stuff aligned
nicely. Maybe in the future I will construct a military-grade
formatter. */
package main
import (
"bufio"
"fmt"
"io"
"os"
"path/filepath"
"regexp"
"strings"
)
const (
ws = " \t"
longestNum = len("1.000.000.000")
)
var (
rv int
reMintageYear = regexp.MustCompile(`^\d{4}(-[^ \t]+)?`)
reMintageRow = regexp.MustCompile(`^(([0-9.]+|\?)[ \t]+)*([0-9.]+|\?)$`)
)
func main() {
if len(os.Args) == 1 {
mfmt("-", os.Stdin, os.Stdout)
}
for _, arg := range os.Args[1:] {
f, err := os.OpenFile(arg, os.O_RDWR, 0)
if err != nil {
warn(err)
continue
}
defer f.Close()
mfmt(arg, f, f)
}
os.Exit(rv)
}
func mfmt(file string, r io.Reader, w io.Writer) {
scanner := bufio.NewScanner(r)
for linenr := 1; scanner.Scan(); linenr++ {
line := strings.Trim(scanner.Text(), ws)
switch {
case len(line) == 0, line[0] == '#':
fmt.Fprintln(w, line)
case reMintageYear.MatchString(line):
fmtMintageYear(line, w)
case reMintageRow.MatchString(line):
fmtMintageRow(line, w)
default:
warn(fmt.Sprintf("%s:%d: potential syntax error", file, linenr))
fmt.Fprintln(w, line)
}
}
}
func fmtMintageYear(line string, w io.Writer) {
switch i := strings.IndexAny(line, ws); i {
case -1:
fmt.Fprintln(w, line)
default:
fmt.Fprintf(w, "%s %s\n", line[:i], strings.TrimLeft(line[i:], ws))
}
}
func fmtMintageRow(line string, w io.Writer) {
tokens := strings.FieldsFunc(line, func(r rune) bool {
return strings.ContainsRune(ws, r)
})
for i, tok := range tokens {
s := formatMintage(tok)
if i == 0 {
fmt.Fprintf(w, "\t%*s", longestNum, s)
} else {
fmt.Fprintf(w, "%*s", longestNum+1, s)
}
}
fmt.Fprintln(w)
}
func formatMintage(s string) string {
if s == "?" {
return s
}
n := atoiWithDots(s)
digits := intlen(n)
dots := (digits - 1) / 3
out := make([]byte, digits+dots)
for i, j := len(out)-1, 0; ; i-- {
out[i] = byte(n%10) + 48
if n /= 10; n == 0 {
return string(out)
}
if j++; j == 3 {
i, j = i-1, 0
out[i] = '.'
}
}
}
func intlen(v int) int {
switch {
case v == 0:
return 1
default:
n := 0
for x := v; x != 0; x /= 10 {
n++
}
return n
}
}
func atoiWithDots(s string) int {
n := 0
for _, ch := range s {
if ch == '.' {
continue
}
n = n*10 + int(ch) - '0'
}
return n
}
func warn(e any) {
fmt.Fprintf(os.Stderr, "%s: %s\n", filepath.Base(os.Args[0]), e)
rv = 1
}
|
